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Byju's Answer
Standard XII
Mathematics
Addition of Vectors
Three forces ...
Question
Three forces
2
^
i
−
^
j
+
3
^
k
,
^
j
+
^
k
and
−
2
^
i
−
2
^
j
+
^
k
are applied on a body. Is the body in equilibrium?
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Solution
Resultant of forces
2
^
i
−
^
j
+
3
^
k
,
^
j
+
^
k
and
−
2
^
i
−
2
^
j
+
^
k
is
(
2
^
i
−
^
j
+
3
^
k
)
+
(
^
j
+
^
k
)
+
(
−
2
^
i
−
2
^
j
+
^
k
)
=
2
^
i
−
^
j
+
3
^
k
+
^
j
+
^
k
−
2
^
i
−
2
^
j
+
^
k
=
−
2
^
j
+
5
^
k
As the resultant force is not zero, the body is not in equilibrium.
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Similar questions
Q.
Three forces
→
A
=
{
^
i
+
^
j
+
^
k
}
,
→
B
=
{
2
^
i
−
^
j
−
3
^
k
}
and
→
C
acting on a body. To keep it in the equilibrium, the value of
→
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is:
Q.
Three bodies of masses
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,
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have position vectors
(
^
i
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j
+
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)
,
(
−
3
^
i
−
2
^
j
+
^
k
)
and
(
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^
i
)
respectively . The centre of mass of this system has position vector
Q.
The points
2
^
i
−
^
j
−
^
k
,
^
i
+
^
j
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^
k
,
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^
i
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Q.
The distance (in units) between the parallel lines
→
r
=
^
i
+
2
^
j
+
3
^
k
+
λ
(
^
i
−
^
j
+
^
k
)
and
→
r
=
2
^
i
−
^
j
−
^
k
+
μ
(
^
i
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^
j
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k
)
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