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Question

Three friend A, B and C have 8, 10 and 12 chocolates respectively. Then has the chocolates which is equal to the average number of chocolates.

A
B
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B
C
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C
A
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Solution

The correct option is A B
Let a be the assumed mean and value of a be 10.
Person No. of chocolates(xi) Deviation
(xia)
A 8 -2
B 10 0
C 12 2

From the above table, we get
sum of deviation =2+0+2=0

Actual mean=Assumed meanActual mean=10

Here, B has 10 chocolates and is equal to the average of distributed number of chocolates.

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