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Question

Three groups A, B, C are contesting for positions on the Board of Directors of a company. The probabilities of their winning are 0.5, 0.3,0.2 respectively. If the group A wins, the probability of introducing a new product is 0.7 and the corresponding probabilities for groups B and C are 0.6 and 0.5 respectively. The probability that the new product will be introduced is given by

A
0.36
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B
0.35
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C
0.63
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D
0.53
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Solution

The correct option is C 0.35
P(A)=0.5,P(B)=0.3,P(C)=0.2
If N is for introducing new product, then
P(N|A)=0.7,P(N|B)=0.6,P(N|C)=0.5
Therefore,
P(N)=P(A)×P(N|A)+P(B)×P(N|B)+P(C)×P(N|C)=0.5×0.7+0.3×0.6+0.2×0.5=0.63

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