Three identical bar magnets, each of pole strength $10 A - m$ and length $10 c m$ are placed in a uniform field of induction $0.05 W b / m^{2}$ . If the three magnets are fastened end to end along the same axis with opposite poles touching each other, resulting magnetic moment in $A m^{2}$ is :

3

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9

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6

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Solution

The correct option is A $3$
In this case, Magnetic Length= $L = 3 \times 0.1 = 0.3 m$
Therefore, $M = m L = 10 \times 0.3 = 3 A - m^{2}$

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Three identical bar magnets, each of pole strength 10 A−m and length 10 cm are placed in a uniform field of induction 0.05 Wb/m2. If the three magnets are fastened end to end along the same axis with opposite poles touching each other, resulting magnetic moment in Am2 is :

The correct option is A 3In this case, Magnetic Length=L=3×0.1=0.3 mTherefore, M=mL=10×0.3=3 A−m2

Three identical bar magnets, each of pole strength $10 A - m$ and length $10 c m$ are placed in a uniform field of induction $0.05 W b / m^{2}$ . If the three magnets are fastened end to end along the same axis with opposite poles touching each other, resulting magnetic moment in $A m^{2}$ is :

The correct option is A $3$
In this case, Magnetic Length= $L = 3 \times 0.1 = 0.3 m$
Therefore, $M = m L = 10 \times 0.3 = 3 A - m^{2}$