Question

Three identical bar magnets of magnetic moment ‘$M$’ are placed in the form of an equilateral $\Delta$ of side ‘$d$’ with ‘$N$’ pole of one touching the south pole of the other. The net magnetic moment of the system is

• A. $M$
• B. $\frac{M}{d}$
• C. $\frac{\sqrt{3}}{2}M$
• D. $0$

Answer 1

The correct option is D $0$

$m_2-M=M_{total}$ ( due to symmetric system its total magnetic moment is 0)
$M_{total}=0$