Three identical bulbs are connected in parallel with a battery of 4.5 V.When all the bulbs glow,the current of 3A is drawn from the battery. (i) What is the amount of current flowing through each bulb? (ii) When one of the bulb gets fused,what happens to the current flowing through other two bulbs? (iii) How much power is dissipated in the circuit when all the three bulbs glow together?

Open in App

Solution

Dear student,

i) potential difference across each each bulb will be same.
Since three bulbs have same resistance, the current will be divided equally through each bulb.
Therefore, each bulb carries 3A / 3 = 1A of current.

ii) when one of the bulb fuses, no current flows though the fused bulb and all the current is distributed through two other bulbs.

iii) P= V x I = 4.5 x x3 = 13.5 W.

Regards

Suggest Corrections

Similar questions

Q. Question 28 (iii)

B_{1}, B_{2}

and

B_{3}

are three identical bulbs connected as shown in Figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(iii) How much power is dissipated in the circuit when all the three bulbs glow together?

Question 28 (i)
$B_{1}, B_{2}$ and $B_{3}$ are three identical bulbs connected as shown in figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(i) What happens to the glow of the other two bulbs when the bulb $B_{1}$ gets fused?

B_{1}, B_{2}

and

B_{3}

are three identical bulbs connected as shown in Figure 12.8. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
What happens to the glow of the other two bulbs when the bulbs

B_{1}

gets fused?

Q. Three identical bulbs are connected in parallel with a battery. The current drawn from the battery is

6 A

. If one of the bulbs gets fused, what will be the total current drawn from the battery ?

Join BYJU'S Learning Program