Three identical cahrges, each having a value $1.0 \times 10^{- 8} C,$ are placed at the corners of an equilateral triangle of side 20 cm. Find th eelectric field and potential at the centre of the triangle

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Solution

$Q = 1.0 \times 10^{- 8} C, L = 20 c m, E = ?, V = ?$
Since it forms an equipotential surface so, the electric field at the centre is 0
$R = (2 \times 10^{- 1})^{2} - (10^{- 1})^{2} = 4 \times 10^{- 2} - 10^{- 2}$
distance of entre from each charge
$= \frac{2}{3} \times 10^{- 2} (4 - 1)$
$= \frac{2}{3} \times 10^{- 1} \times 1.732 = 1.15 \times 10^{- 1} V = 23 \times 10^{2} = 2.3 \times 10^{3} V$

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Three identical cahrges, each having a value 1.0×10−8C, are placed at the corners of an equilateral triangle of side 20 cm. Find th eelectric field and potential at the centre of the triangle

Q=1.0×10−8C,L=20cm,E=?,V=? Since it forms an equipotential surface so, the electric field at the centre is 0 R=(2×10−1)2−(10−1)2=4×10−2−10−2 distance of entre from each charge =23×10−2(4−1) =23×10−1×1.732=1.15×10−1V=23×102=2.3×103V

Three identical cahrges, each having a value $1.0 \times 10^{- 8} C,$ are placed at the corners of an equilateral triangle of side 20 cm. Find th eelectric field and potential at the centre of the triangle