Three identical cells, each of 4 V and internal resistance r, are connected in series to a 6 ohm resistor. If the current flowing in the circuit is 2 A. The internal resistance of each cell is

0.11 ohm

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0. 12 ohm

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0 ohm

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1.1 ohm

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Solution

The correct option is C
0 ohm

Total emf = 3 x 4 = 12 V

Total resistance = 6 + 3r

Current in the circuit = 2 A

Using ohms law

2 = 12/ (6+3r)

2(6+3r)=12
12+6r=12
6r = 12-12 = 0
r = 0/6 = 0

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Three identical cells, each of 4 V and internal resistance r, are connected in series to a 6 ohm resistor. If the current flowing in the circuit is 2 A. The internal resistance of each cell is

The correct option is C 0 ohm Total emf = 3 x 4 = 12 V Total resistance = 6 + 3r Current in the circuit = 2 A Using ohms law 2 = 12/ (6+3r) 2(6+3r)=12 12+6r=12 6r = 12-12 = 0 r = 0/6 = 0

The correct option is C
0 ohm

Total emf = 3 x 4 = 12 V

Total resistance = 6 + 3r

Current in the circuit = 2 A

Using ohms law

2 = 12/ (6+3r)

2(6+3r)=12
12+6r=12
6r = 12-12 = 0
r = 0/6 = 0