1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Three identical circular coils carrying a current 'i' each and having radius a and number of turn one are arranged such that their centers coincide and their planes are mutually perpendicular, Magnitude of the magnetic field at the centre is

A
μ0i2a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3μ0i2a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3μ0i2a
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C √3μ0i2aGiven 3 circular coil perpendicular to each othe and share common centre→B1 is magnetic field of coil in XY plane→B2 is magnetic field of coil in YZ plane→B3 is magnetic field of coil in ZX planeSolution→B1=μ0∗i2a∗ˆk→B2=μ0∗i2a∗ˆi→B3=μ0∗i2a∗ˆjBeff=→B1+→B2+→B3=μ0∗i2a∗(ˆi2+ˆj2+ˆk2)12=312∗μ0∗i2a

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Magnetic Field Due to a Current Carrying Wire
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program