Three identical dipoles are arranged as shown below. What will be the net electric field at P? (K=14πϵ0)
A
k.px3
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B
2kpx3
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C
Zero
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D
√2kpx3
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Solution
The correct option is CZero
Point P lies at equatorial positions of dipole 1 and 2 and axial position of dipole 3. Hence field at P due to dipole 1 E1=k.px3 (towards left) due to dipole 2 E2=k.px2 (towards left) due to dipole 3 E3=k.(2p)x3 (towards right) So net field at P will be zero