Question

Three identical dipoles are arranged as shown below. What will be the net electric field at P? $(K=\frac{1}{4\pi {ϵ}_0})$

• A. $\frac{k.p}{x^3}$
• B. $\frac{2kp}{x^3}$
• C. $Zero$
• D. $\frac{\sqrt{2}kp}{x^3}$

Answer 1

The correct option is C $Zero$



Point P lies at equatorial positions of dipole 1 and 2 and axial position of dipole 3.
Hence field at P due to dipole 1
$E_1=\frac{k.p}{x^3}$ (towards left)
due to dipole 2
$E_2=\frac{k.p}{x^2}$ (towards left)
due to dipole 3 $E_3=\frac{k.\left(2p\right)}{x^3}$ (towards right)
So net field at P will be zero