Question

Three identical particles are joined together by a thread as shown. All the three particles are moving in a horizontal plane. If the velocity of the outermost particle is $v_0$ then the ratio of tensions in the three sections of the string is

• A. 3 : 5 : 6
• B. 3 : 4 : 5
• C. 7 : 11 : 6
• D. 3 : 5 : 7

Answer 1

The correct option is A 3 : 5 : 6

According to the question we know that we have to find the ratio of tension in the three section of string.

so let's suppose angular speed of thread is equal to "W"

by each strings length.

in case of particle $C=T_3=m{W}^{2}3l$.

in case of particle $B=T_2-T_3=m{W}^{2}3l$. so $T_2=m{W}^{2}5l$

in case of particle $A=T_1-T_2=m{W}^{2}2l$ so $T_1=m{W}^{2}6l$.

Hence the ratio will $3:5:6$

Option $A$ is correct .