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Question

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving on a smooth horizontal plane about point O. If the speed of the outermost particle is v0, then the ratio of tensions in the three sections of the string is : (Assume that the string remains straight)
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Solution

According to the question we know that we have to find ratio of tension in the three section of string.
So let's suppose angular speed of thread is equal to 'W' by each string length.
In case of particle C=T3=mW23l=3mW2l
In case of particle B=T2T3=3mW2l so, T2=5mW2l
In case of particle B=T1T2=2mW2l so, T1=6mW2l
Hence the ratio will become 3:5:6


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