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Question

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane in circular path with ‘O’ as center. If the velocity of the outermost particle is v0, then the ratio of tensions in the three sections of the string is

A
3 : 5 : 7
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B
3 : 4 : 5
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C
7 : 11 : 6
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D
3 : 5 : 6
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Solution

The correct option is D 3 : 5 : 6


Let ω is the angular speed of revoultion
T3 =m ω2 3l
T2 - T3 = mω2 2l T2 = mω25l
T1 - T2 = mω2l T1 = mω26l
T3:T2:T1 = 3 : 5 : 6


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