Question

Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane in circular path with ‘O’ as center. If the velocity of the outermost particle is $v_0$, then the ratio of tensions in the three sections of the string is

• A. 3 : 5 : 7
• B. 3 : 4 : 5
• C. 7 : 11 : 6
• D. 3 : 5 : 6

Answer 1

The correct option is D 3 : 5 : 6

Let $\omega$ is the angular speed of revoultion
$T_3$ =m ${\omega }^2$ 3l
$T_2$ - $T_3$ = m${\omega }^2$ 2l $\Rightarrow$ $T_2$ = m${\omega }^{2}5l$
$T_1$ - $T_2$ = m${\omega }^{2}l$ $\Rightarrow$ $T_1$ = m${\omega }^{2}6l$
$T_3$:$T_2$:$T_1$ = 3 : 5 : 6