Question

Three identical particles are joined together by a thread as shown in figure. All the three particles are ~moving on a smooth horizontal plane about point O. If the speed of the outermost particle is $v_0$ then the to ratio of tensions in the three sections of the string is: (Assume that the string remains straight)

• A. $3:5:7$
• B. $3:4:5$
• C. $7:11:6$
• D. $3:5:6$

Answer 1

The correct option is D $3:5:6$

$\omega =\frac{v_o}{3l}$
$T_c=3m{\omega }^{2}l$

$T_b-T_c=3m{\omega }^{2}l$
$T_b=5m{\omega }^{2}l$

$T_a-T_b=m{\omega }^{2}l$
$T_a=6m{\omega }^{2}l$

$T_c:T_b:T_a=3:5:6$