Question

Three identical particles of charge $Q$ and mass $m$ are placed such that they form an equilateral triangle of side $l$ . If they are released simultaneously. The maximum speed attained by any one of the particles will be

• A. $Q\sqrt{\frac{1}{2\pi {\epsilon }_{0}ml}}$
• B. $Q\sqrt{\frac{1}{6\pi {\epsilon }_{0}ml}}$
• C. zero
• D. none of these

Answer 1

The correct option is A $Q\sqrt{\frac{1}{2\pi {\epsilon }_{0}ml}}$

Charge of the particle $=Q$

mass $=m$

side $=l$

maximum speed attained by any one of the particle.

So, Total $PE=\frac{{3KQ}^2}{r}$

$\frac{1}{2}{QV}^2=\frac{1}{4\pi {ϵ}_{0}ml}$

or, $V=Q\sqrt{\frac{1}{2\pi {ϵ}_{0}mL}}$