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Question

Three identical resistors are connected in series. When a certain potential difference is applied across the combination, the total power dissipated is 27 W. How many times the power would be dissipated if the three resistors were connected in parallel across the same potential difference?

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Solution

Given:
Power in series combination Ps=27W
When they are in series : Req=R+R+R=3R,
and PS=V2Req=V23R=27 W
Ps=3×27R W
When they are in parallel: Req=(1/R+1/R+1/R)1=R/3
Power dissipation , PP=V2R/3=3×3PS=9×(27W)=243 W

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