Three identical. spheres of mass in each are placed at the corners of an equilateral triangle of side 2 in. Taking one of the corner as the origin, the position vector of the centre of mass is
A
√3(^i−^j)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
^i√3+^j
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
^i+^j3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
^i+^j√3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is C^i+^j√3 The x coordinate of centre of mass is ¯x=∑mixi∑mi=m×0+m×1+m×2m+m+m=1 ¯y=∑miyi∑mi=m×0+m(2sin60o)+m×0m+m+m=1 ¯y=m√33m=1√3 Position vector of centre of mass is (^i+^j√3)