R.E.F image
As all blocks are moving with
same acceleration (lefts say a) Then
F=(mA+mB+mC)a
F=3Ma
a=F3M
By Newton's second law of motion
→Fnet on a = mA a
→Fnet/A=mAa=mF3m
→Fnet/A=F3
As →Fnet/A=F−N1
⇒73=F−N1
⇒N1=273
Fore on B by A =N1=279
Fore on C by B =N2=mca
=MF3M=F3