Question

Three inductors of $10mH,$ $40mH$ and $50mH$ are connected together in a series combination with no mutual inductance between them. Calculate the total inductance of the series combination.

• A. $100mH$
• B. $6.89mH$
• C. $50mH$
• D. $10mH$

Answer 1

The correct option is A $100mH$

For the series combination of inductors, the equivalent inductance or total inductance is the sum of the individual inductances.

Thus, $L_{net}=L_1+L_2+L_3=10+40+50=100mH$