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Question

Three inductors of 60mH, 120mH and 75mH respectively, are connected together in a parallel combination with no mutual inductance between them. Calculate the total inductance of the parallel combination.

A
20mH
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B
26mH
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C
30mH
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D
28mH
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Solution

The correct option is B 26mH
As the all inductors are connected in parallel combination so the total inductance will be
LT=11/60+1/120+1/75
=1/0.038=26.08=26 mH

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