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Standard XII

Physics

Charge Behaviour

Three infinit...

Question

Three infinite planes have a uniform surface charge density $σ$ on is surface. All charges are fixed.On each of the three infinite planes parallel to the $y - z$ plane placed at $x = - a, x = 0$ and $x = a$ . The potential difference between $A$ and $C$ is:

\frac{σ}{2 ε_{0}} a

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\frac{σ}{ε_{0}} a

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\frac{σ a}{2 ε_{0}}

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Solution

The correct option is D $0$
Apply KVL from A to C
$V_{A} + (\frac{T}{2 ε_{0}}) . a - (\frac{T}{2 ε} . a) = V_{C}$
$= V_{A} = V_{C}$
$V_{A} - V_{V} = 0$

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Three infinite planes have a uniform surface charge density σ on is surface. All charges are fixed.On each of the three infinite planes parallel to the y−z plane placed at x=−a,x=0 and x=a. The potential difference between A and C is:

The correct option is D 0Apply KVL from A to CVA+(T2ε0).a−(T2ε.a)=VC=VA=VCVA−VV=0

Three infinite planes have a uniform surface charge density $σ$ on is surface. All charges are fixed.On each of the three infinite planes parallel to the $y - z$ plane placed at $x = - a, x = 0$ and $x = a$ . The potential difference between $A$ and $C$ is:

The correct option is D $0$
Apply KVL from A to C
$V_{A} + (\frac{T}{2 ε_{0}}) . a - (\frac{T}{2 ε} . a) = V_{C}$
$= V_{A} = V_{C}$
$V_{A} - V_{V} = 0$