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Question

Three light bulbs of 40W, 60W and 100W are connected in series with 220 volt source. Which of the bulbs will grow brightest?

A
60W
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B
40W
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C
100W
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D
All with same brightness
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Solution

The correct option is B 40W
Resistance of 100Wbulb=2002/100=400ohms

Resistance of 60Wbulb=2002/60=666.67ohms

Resistance of 40Wbulb=2002/40=1000ohms

Therefore, total resistance in series = (400+666.67+1000)=2066.67ohms

Current in the circuit =200/2066.67=0.0967A

Therefore, actual power consumed by 40Wbulb=0.09672x1000=9.35W (much lesser than any of the original)

The 40W bulb will grow the brightest as the current is constant in all three and it has the maximum resistance. But it would consume much less than 40W as the bulbs are connected in series, and voltage would be divided across all three filaments depending upon resistances.

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