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Question

Three light strings are connected at the point P. A weight W is suspended from one of the strings. End A of string AP and end B of string PB are fixed as shown. In equilibrium PB is horizontal and PA makes an angle o 60 with the horizontal. If the tension in PB is 30 N then what is the tension in PA and weight W are respectively?
1039756_ca0fef3647834f26aa98a44bb1065b6a.png

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Solution

Force balance
Tsin300=30N
T=60N
W=Tcos300
W=303
Tension the string AP is 60N and weight W is 303

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