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Question

Three lines AB, CD, and EF interesect each other at O.
If AOE=30 and DOB=40, find COF.


A

70

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B

110

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C

55

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D

90

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Solution

The correct option is B

110


From the given figure, we have
AOE+EOD+DOB=180 [Sum of all angles on a straight line is 180]30+EOD+40=180EOD=18070EOD=110
Again, EOD=COF [vertically opposite angles]COF=110


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