Question 94
Three lines AB, CD and EF interesect each other at O. If ∠AOE=30∘ and ∠DOB=40∘ (see the figure). Find ∠COF.
From the given figure, we have
∠AOE+∠EOD+∠DOB=180∘ [∴Sum of all angles on a straight line is 180∘]⇒30∘+∠EOD+40∘=180∘⇒∠EOD=180∘−70∘⇒∠EOD=110∘
Again, ∠EOD=∠COF [vertically opposite angles]⇒∠COF=110∘