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Question
Three lines are drawn in a plane so that there are exactly three different intersection points. Into how many nonoverlapping regions do these lines divide the plane?
Three lines are drawn in a plane so that there are exactly three different intersection points. Into how many nonoverlapping regions do these lines divide the plane?
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Solution
The correct option is E Seven
There are three lines and they intersect exactly at three points.we know that two lines will intersect only at one point.Therefore these three point of intersections will form triangle and the outer space is divided into six regions.Therefore total number of regions is 1+6=7.
There are three lines and they intersect exactly at three points.
we know that two lines will intersect only at one point.
Therefore these three point of intersections will form triangle and the outer space is divided into six regions.
Therefore total number of regions is 1+6=7.
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