Three liquids of densities d,2d and 3d are mixed in equal volumes. Then the density of the mixture is
A
d
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B
2d
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C
3d
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D
5d
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Solution
The correct option is B2d Density of mixture, ρmixture=m1+m2+m3V1+V2+V3
Since V1=V2=V3=V (given) ∴m1=dV,m2=2dV and m3=3dV ⇒ρmixture=dV+2dV+3dV3V =V(d+2d+3d)3V ⇒ρmixture=2d