Three long, straight parallel wires carrying current, are arranged as shown in figure. The force experienced by a 25 cm length of wire C is
A
10-3 N
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B
2.5 X 10-3 N
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C
Zero
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D
1.5 x 10-3 N
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Solution
The correct option is C Zero Force on wire C due to wire D FD=10−7×2×30×102×10−2×25×10−2=5×10−4N..... (towards right) Force on wire C due to wire G FG=10−7×2×20×102×10−2×25×10−2=5×10−4N..... (towards left) ⇒ Net force on wire C is Fnet=FD−FG=0