Question

Three mangoes and three apples are kept in a box. If two fruits are selected at random from the box, the probability that the selection will contain one mango and one apple, is

• A. $\frac{3}{5}$
• B. $\frac{5}{6}$
• C. $\frac{1}{36}$
• D. $None$

Answer 1

The correct option is A $\frac{3}{5}$

There are $3$ mangoes and $3$ apples

The number of ways of selecting $2$ fruits from it is ${{}^{6}C}_2=15$

The number of ways of selecting $1$ mango and $1$ apple is ${{}^{3}C}_1\times {{}^{3}C}_1=9$

The probability is $\frac{9}{15}=\frac{3}{5}$

Therefore option $A$ is correct