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Question

# Three masses 5 kg, 4 kg and 7 kg are aligned in a straight line as shown below. Find the net gravitational force on 4 kg?

A
46.69×1011 N
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B
13.34×1011 N
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C
0
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D
33.5×1011 N
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Solution

## The correct option is B 13.34×10−11 NGravitational force is an attractive force, and the directions of force for the 5 kg and 7 kg mass are shown in the diagram shown. Using the universal law of gravitation for 4 kg and 5 kg mass, we get: F1=GmMAd2A Similarly, F2=GmMBd2B Clearly, the two forces are acting in opposite direction. So, net force will be the difference of the two forces.): F=F2−F1 F=GmMBd2B−GmMAd2A F=Gm(MBd2B−MAd2A) Subsituting values, we get: F=6.67×10−11×4×(722−522) F=13.34×10−11 N

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