Three masses 5kg, 4kg and 7kg are aligned in a straight line as shown below. Find the net gravitational force on 4kg?
A
0
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B
33.5×10−11N
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C
46.69×10−11N
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D
13.34×10−11N
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Solution
The correct option is D13.34×10−11N Gravitational force is an attractive force, and the directions of force for the 5kg and 7kg mass are shown in the diagram shown.
Using the universal law of gravitation for 4kg and 5kg mass, we get: F1=GmMAd2A
Similarly, F2=GmMBd2B
Clearly, the two forces are acting in opposite direction. So, net force will be the difference of the two forces.): F=F2−F1 F=GmMBd2B−GmMAd2A F=Gm(MBd2B−MAd2A)
Subsituting values, we get: F=6.67×10−11×4×(722−522) F=13.34×10−11N