Three masses of 16kg, 8kg and 4kg are placed in contact as shown in figure. If a force of 140 N is applied on 4kg mass, then the force on 16kg will be:
A
140N
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B
120N
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C
100N
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D
80N
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Solution
The correct option is C 80N Treating the body as a single object and using the formula F=m×a where m = combined mass of the system =28kg. Hence, the acceleration =5ms−2Again for the 16 kg block the horizontal force experienced will be 80N.