Question

Three men have $6$ different trousers, $5$ different shirts and $4$ different caps. Number of different ways in which they can wear them is _______

Answer 1

Each will going to wear $1$ trouser, $1$ shirt, $1$ cap

$\therefore$ No. of ways for trousers$=6\times 5\times 4=120$

Shirts$\Rightarrow 5\times 4\times 3=60$

Caps $\Rightarrow 4\times 3\times 2=24$

$\therefore$ Total no. of ways to wear

$\Rightarrow 120\times 60\times 24=172800$ ways.