Three metal cubes of volume $125$ cm $^{3}$ , $64$ cm $^{3}$ and $27$ cm $^{3}$ are melted to form a new cube, then the edge of the new cube formed is

12

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Solution

The correct option is B $6$ cm
New Volume of the cube $= 125 + 64 + 27 = 216 c m^{3}$
Volume $= a^{3} = 216 c m^{3}$
$\Rightarrow a = 6$ cm

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Three metal cubes of volume 125 cm3, 64 cm3 and 27 cm3 are melted to form a new cube, then the edge of the new cube formed is

The correct option is B 6 cmNew Volume of the cube =125+64+27=216cm3Volume =a3=216cm3⇒a=6 cm

Three metal cubes of volume $125$ cm $^{3}$ , $64$ cm $^{3}$ and $27$ cm $^{3}$ are melted to form a new cube, then the edge of the new cube formed is

The correct option is B $6$ cm
New Volume of the cube $= 125 + 64 + 27 = 216 c m^{3}$
Volume $= a^{3} = 216 c m^{3}$
$\Rightarrow a = 6$ cm