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Question

Three metals have work functions in the ratio 2:3:4.When graphs are drawn for all between the stopping potential and the incident frequency. The graphs have slopes in the ratio

A
2: 3: 4
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B
4: 3: 2
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C
6: 4: 3
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D
1: 1: 1
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Solution

The correct option is D 1: 1: 1
Answer is A.
Here equation is
V=(hνϕ)/e
or V=hγeϕe
or comparing with
y=mx+c
we get m=h/e and c=ϕ/e
So, slope, m=h/e
which is a constant.
So, ratio is 1:1:1.

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