Three moles of an ideal monoatomic gas perform a cycle shown in figure. The gas temperature in different states are $T_{1} = 400 K, T_{2} = 800 K, T_{3} = 2400 K,$ and $T_{4} = 1200 K$ . The work done by the gas during the cycle is: $[R = \frac{25}{3} J / m o l - k]$

5kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20kJ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B 20kJ
$Given :$ $T_{1} = 400 K, T_{2} = 800 K, T_{3} = 2400 K, T_{4} = 1200 K$

$Solution :$
$W_{B A} = W_{C D} = 0 (V = c o n s t)$
$W_{B C} = 3 R T_{c} - T_{B}$ P = const
$W_{D A} = 3 R, T_{A} - T_{D}$ P=const
$W = 3 R (T_{A} + T_{c} - T_{B} - T_{D})$ =2400R = 20KJ

$Hence D is the correct option$

Suggest Corrections

Similar questions

T_{1} = 400 K, T_{2} = 800 K, T_{3} = 2400 K a n d T_{4} = 1200 K

T_{A} = 400 K, T_{B} = 800 K, T_{C} = 2400 K, T_{D} = 1200 K .

3

A, B, C, D

T_{A} = 400 K,

T_{B} = 800 K, T_{C} = 2400 K, T_{D} = 1200 K .

3

A B C D A

T_{A} = 400 K, T_{B} = 800 K, T_{C} = 2400 K

T_{D} = 1200 K

(R = 8.314 J / m o l e K)

T_{A} = 400 K, T_{B} = 800 K; T_{C} = 2400 K; T_{D} = 1200 K

Join BYJU'S Learning Program