Question

Three newly wedded couples are dancing at a function. If the partner is selected at random the chance that at least one husband is not dancing with his own wife is

• A. $\frac{1}{3}$
• B. $\frac{1}{6}$
• C. $\frac{5}{6}$
• D. $\frac{2}{3}$

Answer 1

Answer: (C)

$\frac{5}{6}$

Total ways of choosing partners $=3!=6$
Probability that at least one husband is not dancing with his own wife
$=1-$ probability that all husbands are dancing with their wives
$=1-1/6=5/6$