Let the numbers be a−d,a,a+d
Squares of these number form a GP
(a−d)2,a2,(a+d)2
⇒(a2)2=(a−d)2(a+d)2
⇒a4=(a2−d2)2
⇒a2=a2−d2ora2=d2−a2
⇒d=0ord=±√2a
From 1st case not possible as the numbers are distinct
r=a2(a−d)2
also r=(a+d)2a2
substitue d as obtained above and get the possible values of r .