1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Three numbers are chosen at random without replacement from 1,2,3,.....,10. The probability that the minimum of the chosen numbers is 3 or their maximum is 7 is

A
1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1/3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1/4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
11/40
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 11/40Selection of 3 no.'s from {1,2,3,4,5,6,7,8,9,10}⇒ No.of combinations to be made=10C3Selection of 3 no.'s having 3 as minimum should be selected from the set {3,4,5,6,7,8,9,10} for which one number is fixed i.e.,3⇒ No.of combinations to be made=7C2selection of 3 no.'s having 7 as maximum should be selected from the set {1,2,3,4,5,6,7} for which one number is fixed i.e.,7⇒ No.of combinations to be made=6C2selection of 3 no.'s having 7 as maximum and 3 as minimum should be selected from the set {3,4,5,6,7} for which two numbers fixed i.e.,3 and 7⇒ No.of combinations to be made=3C1Therefore the probability that the minimum of the chosen numbers is 3 or their maximum is 7 is=(7C2+6C2−3C110C3)=(21+15−3)120=33120=1140

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program