Question

Three numbers are in A.P. whose sum is 33 and product is 792, then the smallest positive number from these numbers is

• A. 4
• B. 8
• C. 11
• D. 14

Answer 1

The correct option is A 4

Let three number in A.P are $a-d,a,a+d$
Given sum $=33\Rightarrow a=11$
Also product $=(11-d)\left(11\right)(11+d)=792$
$\Rightarrow 121-d^2=72\Rightarrow d=\pm 7$
Thus A.P is $4,11,18$ or $18,11,4$.
Hence, option 'A' is correct.