Three numbers are in the ratio $2 : 3 : 4$ to one another. The sum of their cubes is $0.334125$ . Find the numbers.

0.08

0.12

0.16

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0.6

0.9

0.12

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0.3

0.45

0.6

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0.10

0.15

0.20

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Solution

The correct option is C $0.3$ , $0.45$ , $0.6$
$(2 x)^{3} + (3 x)^{3} + (4 x)^{3} = 0.334125$

$8 x^{3} + 27 x^{3} + 64 x^{3} = 0.334125$

$99 x^{3} = 0.334125$

$x = 0.15$

The three numbers are $2 (0.15) = 0.3, 3 (0.15) = 0.45 o r 4 (0.15) = 0.6$

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Similar questions

Three numbers are in ratio 2:3:4. The sum of their cubes is 0.334125. Find the numbers.

\frac{1}{\sqrt{0. ¯ ¯ ¯ 2} + \sqrt{0. ¯ ¯ ¯ 4}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 4} + \sqrt{0. ¯ ¯ ¯ 6}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 6} + \sqrt{0. ¯ ¯ ¯ 8}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 10} + \sqrt{0. ¯ ¯¯¯ ¯ 12}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 12} + \sqrt{0. ¯ ¯¯¯ ¯ 14}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 14} + \sqrt{0. ¯ ¯¯¯ ¯ 16}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 16} + \sqrt{0. ¯ ¯¯¯ ¯ 18}} + . . . . . .

. . . . . . . . . . . . . . . + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 38} + \sqrt{0. ¯ ¯¯¯ ¯ 40}} = \frac{3}{2} (\sqrt{a} + \sqrt{b}),

\frac{1}{\sqrt{0. ¯ ¯ ¯ 2} + \sqrt{0. ¯ ¯ ¯ 4}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 4} + \sqrt{0. ¯ ¯ ¯ 6}} + \frac{1}{\sqrt{0. ¯ ¯ ¯ 6} + \sqrt{0. ¯ ¯ ¯ 8}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 10} + \sqrt{0. ¯ ¯¯¯ ¯ 12}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 12} + \sqrt{0. ¯ ¯¯¯ ¯ 14}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 14} + \sqrt{0. ¯ ¯¯¯ ¯ 16}} + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 16} + \sqrt{0. ¯ ¯¯¯ ¯ 18}} + . . . . . .

. . . . . . . . . . . . . . . + \frac{1}{\sqrt{0. ¯ ¯¯¯ ¯ 38} + \sqrt{0. ¯ ¯¯¯ ¯ 40}} = \frac{3}{2} (\sqrt{a} + \sqrt{b}),

2 : 3 : 4

33957

Question 134

Solve the following question:

Three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 0.334125. Find the numbers.

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