Three numbers are in the ratio of $3 : 4 : 6$ and their product is $1944$ . The largest of these number is :

6

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12

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18

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t h e s e

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Solution

The correct option is C $18$
Let the numbers be $3 x, 4 x, 6 x$ .
Since,
$3 x \times 4 x \times 6 x = 1944$
$72 x^{3} = 1944$
$x^{3} = 27$
$x = 3$
Therefore, the largest number
$= 6 \times 3 = 18$ .

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