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Question

Three observers A, B and C measure the speed of light coming from a source to be νA, νB and νC. A moves towards the source and C moves away from the source at the same speed. B remains stationary. The surrounding space is vacuum everywhere.
(a) νA>νB>νC
(b) νA<νB<νC
(c) νA=νB=νC
(d) νB=12νA+νC.

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Solution

(c) vA = vB = vC
(d) νB=12vA+vC
Since the speed of light is a universal constant, vA = vB = vC = 3×108 m/s.
νB=12vA+vC. This expression also implies that vA = vB = vC.
1
νs=12

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