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Standard VIII

Physics

Refraction through a Rectangular Glass Slab

Three observe...

Question

Three observers A, B and C measure the speed of light coming from a source to be ν_A, ν_B and ν_C. A moves towards the source and C moves away from the source at the same speed. B remains stationary. The surrounding space is vacuum everywhere.
(a) $ν_{A} > ν_{B} > ν_{C}$
(b) $ν_{A} < ν_{B} < ν_{C}$
(c) $ν_{A} = ν_{B} = ν_{C}$
(d) $ν_{B} = \frac{1}{2} (ν_{A} + ν_{C})$ .

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Solution

(c) v_A₌v_B₌ v_C
(d) $ν_{B} = \frac{1}{2} (v_{A} + v_{C})$

Since the speed of light is a universal constant, v_A₌v_B₌ v_C= $3 \times 10^{8}$ m/s.
$ν_{B} = \frac{1}{2} (v_{A} + v_{C})$ . This expression also implies that v_A₌v_B₌ v_C_.
1
νs=12

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(c) vA = vB = vC (d) νB=12vA+vC Since the speed of light is a universal constant, vA = vB = vC = 3×108 m/s. νB=12vA+vC. This expression also implies that vA = vB = vC. 1 νs=12

(c) v_A₌v_B₌ v_C
(d) $ν_{B} = \frac{1}{2} (v_{A} + v_{C})$

Since the speed of light is a universal constant, v_A₌v_B₌ v_C= $3 \times 10^{8}$ m/s.
$ν_{B} = \frac{1}{2} (v_{A} + v_{C})$ . This expression also implies that v_A₌v_B₌ v_C_.
1
νs=12