Question

Three oxides of nitrogen, $NO,N{O}_2$ and $N_{2}O$, can be formed under different conditions.
Complete the table to give the oxidation numbers of nitrogen in $NO$ and $N{O}_2$.

Compound	$NO$	$N{O}_2$
Oxidation number of $N$

Answer 1

Solution:-

Let $x$ and $y$ be the oxidation state of nitrogen in $NO$ and $N{O}_2$ respectively.

Oxidation state of oxygen $=-2$

Therefore,

In $NO$-

$x+(-2)=0$

$\Rightarrow x=+2$

In $N{O}_2$-

$x+2\times (-2)=0$

$\Rightarrow x=+4$