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Standard XII

Physics

Conservation of Momentum

Three particl...

Question

Three particles A, B and C of equal mass, move with equal speed v along the medians of an equilateral triangle as shown in the figure. They collide at centroid G of the triangle. After collision, A comes to rest and B retracts its path with speed v. What is the speed of C after collison?

zero

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\frac{v}{2}

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Solution

The correct option is C v
The resultant momentum of the system is zero because vector sum of momentum of B and C is equal and opposite to that of A.
Now , as their is no external force (collision is internal to the system) momentum of the system will be conserved.
Therefore final momentum will also be zero.
given, A comes to rest and B retraces back its path with same velocity, C will go along the line joining B to the median but in opposite direction.

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