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Question
Three particles α,β and γ of equal mass are moving with the same velocity v along the medians of an equilateral triangle. After collision, α becomes stationary, β retraces its path with velocity v, then the magnitude and direction of γ will be :
Three particles α,β and γ of equal mass are moving with the same velocity v along the medians of an equilateral triangle. After collision, α becomes stationary, β retraces its path with velocity v, then the magnitude and direction of γ will be :
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Solution
The correct option is C v and opposite to β
The particle of same mass and same magnitude of velocities on medians of an equilateral triangle, in total have zero momentum as they form a cyclic system. Ex. triangle. Hence the momentum after collision will also be zero.
As α becomes stationary, β retraces its path with velocity v, so to make momentum 0, γ has to move opposite to β with same speed.
The particle of same mass and same magnitude of velocities on medians of an equilateral triangle, in total have zero momentum as they form a cyclic system. Ex. triangle. Hence the momentum after collision will also be zero.
As α becomes stationary, β retraces its path with velocity v, so to make momentum 0, γ has to move opposite to β with same speed.
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