Three particles $α$ -particle, proton and deuteron are accelerated by the same potential difference. What is the ratio of kinetic energy :

1 : \sqrt{2} : 1

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1 : 1 : \sqrt{2}

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1 : 2 : 4

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4 : 2 : 1

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Solution

The correct option is C $1 : 2 : 4$
$\begin{matrix} W o r k d o n e = c h a n g e i n K E q V = K E A s V i s c o n s tan t, R a t i o o f K . E = q_{1} : q_{2} : q_{3} = 1 : 2 : 4 \end{matrix}$
Option $C$ is correct .

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Three particles α-particle, proton and deuteron are accelerated by the same potential difference. What is the ratio of kinetic energy :

The correct option is C 1:2:4Workdone=changeinKEqV=KEAsVisconstant,RatioofK.E=q1:q2:q3=1:2:4Option C is correct .

Three particles $α$ -particle, proton and deuteron are accelerated by the same potential difference. What is the ratio of kinetic energy :

The correct option is C $1 : 2 : 4$
$\begin{matrix} W o r k d o n e = c h a n g e i n K E q V = K E A s V i s c o n s tan t, R a t i o o f K . E = q_{1} : q_{2} : q_{3} = 1 : 2 : 4 \end{matrix}$
Option $C$ is correct .