You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Gravitational Force

Three particl...

Question

Three particles, each of mass $m$ , are fixed at the vertices of an equilateral triangle of side length $a$ . The only forces acting on the particles are their mutual gravitational forces. Then answer the following question.
The gravitational potential at $O$ is

\frac{- 3 G m}{a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 3 \sqrt{3} G m}{a}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{- 6 G m}{a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 4 \sqrt{3} G m}{a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{- 3 \sqrt{3} G m}{a}$

Net potential at point $O$ is the sum of potentials experienced by individual charges
So, $V = \frac{- G m}{d} \times 3$
$V = \frac{- 3 G m}{\frac{a}{\sqrt{3}}} = \frac{- 3 \sqrt{3} G m}{a}$

Suggest Corrections

Similar questions

Q. Three particles, each of mass

m

, are fixed at the vertices of an equilateral triangle of side length

a

. The only forces acting on the particles are their mutual gravitational forces. Then answer the following question.
Force acting on particle

C

, due to particle

A

and

B

Q. Three particles, each of mass

m

are situated at the vertices of an equilateral triangle of side

a

. The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle should move in a circle while maintaining the original mutual separation

a

. Then their time period of revolution is :

Three particles each of mass m, are situated at the vertices of an equilateral triangle of side length a. The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original separation a. Find the initial velocity that should be given to each particle and also the time required for the circular motion

Three particles, each of mass m, are situated at the vertices of an equilateral triangle of side 'a'. The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining their original separation 'a'. The initial velocity that should be given to each particle and time period of circular motion are respectively

Q. Three partieles, each of mass

m

are situated at the vertices of an equilateral triangle of side

a

. The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation

a

. Find the initial velocity that should be given to each particle and also the time period of the circular motion.

(F = \frac{G m_{1} m_{2}}{r^{2}})

Join BYJU'S Learning Program

Three particles, each of mass m, are fixed at the vertices of an equilateral triangle of side length a. The only forces acting on the particles are their mutual gravitational forces. Then answer the following question.The gravitational potential at O is

The correct option is B −3√3GmaNet potential at point O is the sum of potentials experienced by individual chargesSo, V=−Gmd×3 V=−3Gma√3=−3√3Gma

Three particles, each of mass $m$ , are fixed at the vertices of an equilateral triangle of side length $a$ . The only forces acting on the particles are their mutual gravitational forces. Then answer the following question.
The gravitational potential at $O$ is

The correct option is B $\frac{- 3 \sqrt{3} G m}{a}$

Net potential at point $O$ is the sum of potentials experienced by individual charges
So, $V = \frac{- G m}{d} \times 3$
$V = \frac{- 3 G m}{\frac{a}{\sqrt{3}}} = \frac{- 3 \sqrt{3} G m}{a}$